Solve this: 15 Divide he polynomial: a) Acirc; nbsp; Acirc; nbsp;(9x2 Acirc; nbsp;+ Acirc; nbsp;3x) Acirc; nbsp; Atilde; middot; Acirc; nbsp;3xb) Acirc; nbsp;(14y3 Acirc; nbsp;- Acirc; nbsp;140xy) Acirc; nbsp; Atilde; middot; Acirc; nbsp;7xyc) Acirc; nbsp;96abc Acirc; nbsp;(30 Acirc; nbsp;-12) Acirc; nbsp;(5b Acirc; nbsp;- Acirc; nbsp;30) Acirc; nbsp; Atilde; middot; Acirc; nbsp;144(a-4) Acirc; nbsp;(b-6)d) Acirc; nbsp;52x Acirc; nbsp;+ Acirc; nbsp;1 Acirc; nbsp;(3x Acirc; nbsp;+5) Acirc; nbsp; Atilde; middot; Acirc; nbsp;(10x Acirc; nbsp;+5)e) Acirc; nbsp;44(x2 Acirc; nbsp;- Acirc; nbsp;5x3-24x2) Acirc; nbsp; Atilde; middot; Acirc; nbsp;11x Acirc; nbsp;(x-8)

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Anuradha Chikane asked in Math

Solve this:

15. Divide he polynomial:

$a) (9 x^{2} + 3 x) \div 3 x b) (14 y^{3} - 140 x y) \div 7 x y c) 96 a b c (30 - 12) (5 b - 30) \div 144 (a - 4) (b - 6) d) 5 (2 x + 1) (3 x + 5) \div (10 x + 5) e) 44 (x^{2} - 5 x^{3} - 24 x^{2}) \div 11 x (x - 8)$

Neha Sethi answered this

Dear student

a) (9 x^{2} + 3 x) \div 3 x = \frac{9 x^{2} + 3 x}{3 x} = \frac{3 x (3 x + 1)}{3 x} = 3 x + 1 b) (14 y^{3} - 140 xy) \div 7 xy = \frac{14 y^{3} - 140 xy}{7 xy} = \frac{7 y (2 y^{2} - 20 x)}{7 xy} = \frac{2 y^{2} - 20 x}{x} = \frac{2 (y^{2} - 10 x)}{x} d) 5 (2 x + 1) (3 x + 5) \div (10 x + 5) = \frac{5 (2 x + 1) (3 x + 5)}{10 x + 5} = \frac{(10 x + 5) (3 x + 5)}{10 x + 5} = 3 x + 5

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