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Bakul Biswas answered this

Dear Student,

The value of the acceleration is given as:

$a=10{\text{mm}}^{-2}=\frac{10\times {10}^{-3}}{{\displaystyle \frac{1}{(60\times 60{)}^{2}}}}{\text{km/h}}^{2}=3600\times {10}^{-2}{\text{km/h}}^{2}=36{\text{km/h}}^{2}\phantom{\rule{0ex}{0ex}}$

The value of the acceleration is given as:

$a=10{\text{mm}}^{-2}=\frac{10\times {10}^{-3}}{{\displaystyle \frac{1}{(60\times 60{)}^{2}}}}{\text{km/h}}^{2}=3600\times {10}^{-2}{\text{km/h}}^{2}=36{\text{km/h}}^{2}\phantom{\rule{0ex}{0ex}}$

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