Five boys were assigned to help to carry some tables in the classroom. Each boy was given the same number of tables to carry. However,one boy was ill and as a result,each of the remaining 4 boys had to carry extra 2 tables. How many tables did they carry altogether ?

Shruti Tyagi answered this

Dear student,

$Letthenumberoftabletscarriedbyeachboysbe\text{'}x\text{'}\phantom{\rule{0ex}{0ex}}No.oftabletscarriedby5boys=5x\phantom{\rule{0ex}{0ex}}Whenoneboywasill,theneachboycarried(x+2)tablets\phantom{\rule{0ex}{0ex}}No.oftabletscarriedby4boys=4\left(x+2\right)\phantom{\rule{0ex}{0ex}}Acc.toquestion,\phantom{\rule{0ex}{0ex}}5x=4\left(x+2\right)\phantom{\rule{0ex}{0ex}}\Rightarrow 5x=4x+8\phantom{\rule{0ex}{0ex}}\Rightarrow 5x-4x=8\phantom{\rule{0ex}{0ex}}\Rightarrow \overline{)x=8}\phantom{\rule{0ex}{0ex}}Thuetheno.oftabletscarriedaltogether=5x=5\times 8=40$

Regards

$Letthenumberoftabletscarriedbyeachboysbe\text{'}x\text{'}\phantom{\rule{0ex}{0ex}}No.oftabletscarriedby5boys=5x\phantom{\rule{0ex}{0ex}}Whenoneboywasill,theneachboycarried(x+2)tablets\phantom{\rule{0ex}{0ex}}No.oftabletscarriedby4boys=4\left(x+2\right)\phantom{\rule{0ex}{0ex}}Acc.toquestion,\phantom{\rule{0ex}{0ex}}5x=4\left(x+2\right)\phantom{\rule{0ex}{0ex}}\Rightarrow 5x=4x+8\phantom{\rule{0ex}{0ex}}\Rightarrow 5x-4x=8\phantom{\rule{0ex}{0ex}}\Rightarrow \overline{)x=8}\phantom{\rule{0ex}{0ex}}Thuetheno.oftabletscarriedaltogether=5x=5\times 8=40$

Regards