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Kakembo James asked in Math

a force of 100 Newtons stretches and elastic Sprint by 2 centimeters what force would stretch The Same spring by 3.5cm

Thank You
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Sanat K Mukherjee answered this

Dear Student,
Let k be the spring constant. So, the magnitude of force required to stretch a spring by x = 2 cm = 0.02m is given as:
F = kx = 100NThus, k = 100N0.02m = 5000N/m
Thus, magnitude of force required to stretch the same spring by 3.5 cm is F'=kx'=5000Nm×0.035m=175N.
Regards,