a force of 100 Newtons stretches and elastic Sprint by 2 centimeters what force would stretch The Same spring by 3.5cm

Sanat K Mukherjee answered this

Dear Student,

Let k be the spring constant. So, the magnitude of force required to stretch a spring by x = 2 cm = 0.02m is given as:

$\left|\begin{array}{c}F\end{array}\right|=kx=100N\phantom{\rule{0ex}{0ex}}Thus,k=\frac{100N}{0.02m}=5000N/m$

Thus, magnitude of force required to stretch the same spring by 3.5 cm is $F\text{'}=kx\text{'}=5000\frac{N}{m}\times 0.035m=175N$.

Regards,

Let k be the spring constant. So, the magnitude of force required to stretch a spring by x = 2 cm = 0.02m is given as:

$\left|\begin{array}{c}F\end{array}\right|=kx=100N\phantom{\rule{0ex}{0ex}}Thus,k=\frac{100N}{0.02m}=5000N/m$

Thus, magnitude of force required to stretch the same spring by 3.5 cm is $F\text{'}=kx\text{'}=5000\frac{N}{m}\times 0.035m=175N$.

Regards,